Russell Wilson is off to the best start to a season of his eight-year career, and his play is a big reason why the Seahawks have opened the year with two wins.
And after helping lead a 28-26 victory in Pittsburgh by throwing three touchdown passes and completing 82.9 percent of his passes, Wilson has been named the NFC Offensive Player of the Week. It's Wilson's first Player of the Week nod since the 2017 season, and the eighth of his career, moving him past running back Shaun Alexander for the most in team history.
In Sunday's win at Pittsburgh, Wilson completed 29 of 35 attempts for 300 yards and three touchdowns, giving him a passer rating of 131.0. It was the 22nd game of Wilson's career with three or more touchdowns and no interceptions, and he has thrown two or more without an interception 45 times, the most in NFL history for a quarterback in his first eight years—and Wilson has 14 more games to add to that total in Year 8. A week earlier, Wilson was an efficient 14 of 20 for 195 yards, two touchdowns and no interceptions.
"Russell was phenomenal all day long," Seahawks coach Pete Carroll said after the game in Pittsburgh.
"He's a Hall of Fame caliber quarterback man, he does it all," added left tackle Duane Brown said. "His leadership is amazing throughout the game. He's 100 percent locked in and engaged with everyone. It was a different game plan than what we're used to—we threw the ball 35-plus times, and he had 80 percent completion rate, three touchdowns, and was just in control throughout the game. He's running the ball, making plays with his legs, he's blocking down field. I'm just happy he's on my team. He's a phenomenal player and a great leader."
